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5b^2-6b-8=0
a = 5; b = -6; c = -8;
Δ = b2-4ac
Δ = -62-4·5·(-8)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-14}{2*5}=\frac{-8}{10} =-4/5 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+14}{2*5}=\frac{20}{10} =2 $
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